Question

A man has a combination of $1 and $20 bills in his pocket. If the number of $1 bills is one less than 6times the number of $20 bills and he has $51, determine the number of each bill he has.Express the situation as a system of equations. Assume x as number of $1 bills and y as number of$20 bills.x +y = 51y-

Answer 1

ANSWER:

$\begin{gathered} 1x+20y=51 \\ x=6y-1 \end{gathered}$

STEP-BY-STEP EXPLANATION:

We can propose two equations, one regarding the total value of money and the other regarding the total number of bills.

Therefore, it would be:

$\begin{gathered} 1x+20y=51 \\ x=6y-1 \end{gathered}$