Question

I Problem #1The figure above is made of 4 equal squares with side length of 8, and 2 half circles. Find the perimeter of the figure in terms of 7 (leaved as it is). Note:The perimeter does not include the lines inside the shape, just the outline of the entire figure.

Answer 1

$\text{Perimeter}_{figure}=98.26\text{ m}$

Explanation

Perimeter is the distance around a two-dimensional shape. Add the side lengths to find the perimeter of regular polygons

Step 1

Let

diameter of the circle=2*8=16

Now, the perimeter is=(6*8)+2 perimeter of half circle

$\begin{gathered} \text{perimeter of the circle}=\text{diameter}\cdot\pi \\ \text{then} \end{gathered}$$\begin{gathered} \text{Perimeter}_{figure}=(6\cdot8\text{ m)+2}\frac{\text{(16}\cdot\pi)}{2} \\ \text{Perimeter}_{figure}=48\text{ m+}16\pi \\ \text{Perimeter}_{figure}=48\text{ m+50.26 m} \\ \text{Perimeter}_{figure}=98.26\text{ m} \end{gathered}$

I hope this helps you