how did the solution appear after you mixed 3 ml of 0.1 m copper(ii) sulfate with 3 ml of 0.1 m sodium sulfide?

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31-10-2022
Chemistry

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how did the solution appear after you mixed 3 ml of 0.1 m copper(ii) sulfate with 3 ml of 0.1 m sodium sulfide?

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rafikiedu08 rafikiedu08 · Answer 1 · 2022-11-03T10:32:19+01:00

colorless with a black precipitation the solution appear after you mixed 3 ml of 0.1 m copper(ii) sulfate with 3 ml of 0.1 m sodium sulfide.

The solution is colorless and a black precipitate appears after 3 mL of 0.1 M sodium sulfide and 3 mL of 0.1 M copper(II) sulfate are combined. There are an equal number of moles of each reactant when 3 mL of 0.1 M sodium sulfide and 3 mL of 0.1 M copper(II) sulfate are combined. When 3 mL of each solution are combined, the balanced reaction shows that the reactants combine in a 1:1 mole ratio, leaving no excess reactants behind. As a result, the final mixture includes the colorless aqueous sodium sulfate solution as well as the dark copper(II) sulfide precipitate. By mixing the test solution with the supernatant, this can be verified.

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