Step 1
It is known that pH is calculated as follows:
[tex]\begin{gathered} pH\text{ = - log }\lbrack H3O+\rbrack \\ \lbrack H3O+\rbrack\text{ = concentracion in M} \end{gathered}[/tex]------------
Step 2
Information provided:
[H3O+] = 3.2×10^−9 M
------------
Step 3
Procedure:
From step 1:
pH = -log [H3O+]
pH = -log (3.2×10^−9 M) = 8.49
Answer: pH = 8.49