Respuesta :

Step 1

It is known that pH is calculated as follows:

[tex]\begin{gathered} pH\text{ = - log }\lbrack H3O+\rbrack \\ \lbrack H3O+\rbrack\text{ = concentracion in M} \end{gathered}[/tex]

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Step 2

Information provided:

[H3O+] = 3.2×10^−9 M

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Step 3

Procedure:

From step 1:

pH = -log [H3O+]

pH = -log (3.2×10^−9 M) = 8.49

Answer: pH = 8.49

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