Question

can someone help. plsWhich is the equation of the line through the points (-3,4) and (5,4)?

Answer 1

First, you can find the slope of the line using the equation

$m=\frac{y_2-y_1}{x_2-x_1}$

If you take (-3,4) as P1 and (5,4) as P2 you have

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{4-4}{5-(-3)}=\frac{0}{5+3}=\frac{0}{8}=0$

Then, to obtain the equation of the line you can use the equation point slope, that is

$y-y_1=m(x_{}-x_1)$

And so you get

$\begin{gathered} y-y_1=m(x_{}-x_1) \\ y-4=0(x-(-3)) \\ y-4=0 \\ y=4 \end{gathered}$

Therefore, the equation of the line that passes through the points (-3,4) and (5,4) is y=4.