The weight of the diver in newtons is 770 N.
The total decrease or increase in the gravitational potential energy of the diver and Earth system can be given by,
∆U = mg∆h
Where,
ΔU is the change in gravitational potential energy,
m the mass of the diver,
g is acceleration due to gravity,
∆h is the total change in height.
It is given that the change in gravitational potential energy is 28500 joules and the change in height is 37 m.
Now putting all the values,
28500 = mg(37)
m = 770 Kg.
Hence, weight of the diver is 770N.
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