Taking the given equation to its slope-intercept form we get:
[tex]\begin{gathered} -10x+9y+10x=13+10x, \\ 9y=10x+13, \\ \frac{9y}{9}=\frac{10x+13}{9}, \\ y=\frac{10}{9}x+\frac{13}{9}\text{.} \end{gathered}[/tex]Answer: The slope of the given line is:
[tex]\frac{10}{9}\text{.}[/tex]