Question

Sulfurous acid, h2so3, breaks down into water (h2o) and sulfur dioxide (so2). if only one molecule of sulfurous acid was involved in a chemical reaction, how many sulfur (s) atoms would be in the products?

Answer 1

Explanation:

The given reaction equation will be as follows.

  $H_{2}SO_{3} \rightarrow H_{2}O + SO_{2}$

Now, number of atoms on reactant side are as follows.

• H = 2

• S = 1

• O = 3

Number of atoms on product side are as follows.

• H = 2

• S = 1

• O = 3

Therefore, this equation is balanced since atoms on both reactant and product sides are equal.

Thus, we can conclude that there is one sulfur atom in the products.

Answer 2

Answer:1 atom of sulfur

Explanation: