Question

U cubed + 3u squared minus 6 divided by u + 4

Answer 1

The first step is to write the division in an equation form:

Now find a term to multiply u+4 that can be canceled with u^3 (the first term) and so for each term

$\frac{u^3+3u^2-6}{u+4}$

Now the answer is

$u^2+3u-16+\frac{58}{u+4}$