. a sample of helium gas in a piston has a volume of 86.4 ml under a pressure of 447 torr. what will be the volume of the helium if the pressure on the piston is increased to 1,240 torr? assume that the temperature and the amount of the gas remain constant.

Respuesta :

Boyle's Rule: If the temperature and volume of the ideal gas remain constant in a closed system, the absolute pressure that a given mass of the gas exerts is inversely proportional to the space it takes up.

P1V1 = P2V2

447 × 86.4 = 1240 × V2

V2 = 447 × 86.4 / 1240

V2 = 31.146 mL

At constant temperature (T) and molecular weight (M), volume (V) decreases as pressure (P) increases (n)

PV = nRT

V = nRT/P

V = 4.55 × 0.082 × 285 / 7.32

Where R = ideal gas constant = 0.082 (L) (atm) (mole) -1(K) -1

V is equal to 14.53 L or 14530 cm3.

Charles's Rule: When pressure is held constant, a given mass of gas has a straight relationship between its volume and absolute temperature.

V1T2 = V2T1

1 × 263 = V2 × 310

V2 = 1 × 310 / 263

V2 = 1. 179 L

Volume (V) increases at constant pressure (P) and mole as temperature (T) rises (n)

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