Respuesta :

we use the formula of the area

[tex]A=\pi\times r^2[/tex]

where A is the area and r the radious

Radious

we can replace the value of the area and solve for r

[tex]\begin{gathered} 36\pi=\pi\times r^2 \\ \\ r^2=\frac{36\pi}{\pi} \\ \\ r^2=36 \\ r=6 \end{gathered}[/tex]

Value of the radious is 6inches

Diameter

diameter is twice radious

[tex]\begin{gathered} d=6\times2 \\ d=12 \end{gathered}[/tex]

Value of the diamter is 12 inches

Circumference

we use the formula of the periemter

[tex]P=2\pi\times r[/tex]

and replace the value of radious

[tex]\begin{gathered} P=2\pi\times6 \\ P=12\pi \end{gathered}[/tex]

Value of the circumference is 12pi inches

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