we use the formula of the area
[tex]A=\pi\times r^2[/tex]where A is the area and r the radious
Radious
we can replace the value of the area and solve for r
[tex]\begin{gathered} 36\pi=\pi\times r^2 \\ \\ r^2=\frac{36\pi}{\pi} \\ \\ r^2=36 \\ r=6 \end{gathered}[/tex]Value of the radious is 6inches
Diameter
diameter is twice radious
[tex]\begin{gathered} d=6\times2 \\ d=12 \end{gathered}[/tex]Value of the diamter is 12 inches
Circumference
we use the formula of the periemter
[tex]P=2\pi\times r[/tex]and replace the value of radious
[tex]\begin{gathered} P=2\pi\times6 \\ P=12\pi \end{gathered}[/tex]Value of the circumference is 12pi inches