Question

Solve for x: 4•2^5 = 21 А. 0.42ОВ. 0.48ооооОс. 0.31OD D. 0.08

Answer 1

Answer:

B. 0.48

Explanation:

Given the below;

$4\cdot2^{5x}=21$

We'll follow the below steps to solve for x;

Step 1: Divide both sides of the equation by 4;

$\begin{gathered} \frac{4\cdot2^{5x}}{4}=\frac{21}{4} \\ 2^{5x}=\frac{21}{4} \end{gathered}$

Step 2: Take the natural log of both sides of the equation;

$\begin{gathered} \ln (2^{5x})=\ln (\frac{21}{4}) \\ 5x\ln 2=\ln (\frac{21}{4}) \end{gathered}$

Step 3: Divide both sides by 5 ln 2;

$\begin{gathered} x=\frac{\ln (\frac{21}{4})}{5\ln 2} \\ x=0.48 \end{gathered}$