We want to identify what pair of triangles are similar on the figure shown.
For doing so, we will use what we are given: GRPC is a parallelogram, and the measures on the graph, to find some values.
We have that:
[tex]GR=CP=CB+BP=325ft+225ft=550ft[/tex]
Also,
[tex]GC=RP=375ft[/tex]
Part A and B
For this part, we will identify similar triangles. We say that:
[tex]\begin{gathered} \Delta GCB\sim\Delta BEP \\ \Delta GCB\sim\Delta GRE \end{gathered}[/tex]
First, we will show that the triangles GCB and BEP are similar. This happens because the angles
[tex]\angle EBP\cong\angle CBG\text{ as they are opposite by the vertex}[/tex]
And:
[tex]\angle BGC\cong\angle BEP[/tex]
as the lines GC and RP are parallel (because GRPC is a parallelogram) and the line BG is a transversal to parallel lines. Thus, by the criteria AA, the triangles are similar.
Now, we will show that the triangles GCB and GRE are similar.