Question

Write down the first five terms of the sequence an=8nn+8 a1 = a2 = a3 = a4 = a5 =

Answer 1

$a_n=\frac{8n}{n+8}$

First term: Evaluate the expression above for n=1:

$a_1=\frac{8(1)}{1+8}=\frac{8}{9}$

Second term: evaluate the expression for n=2:

$a_2=\frac{8(2)}{2+8}=\frac{16}{10}=\frac{8}{5}$

Third term: evaluate the expression for n=3:

$a_3=\frac{8(3)}{3+8}=\frac{24}{11}$

Fourth term: evaluate the expression for n=4:

$a_4=\frac{8(4)}{4+8}=\frac{32}{12}=\frac{8}{3}$

Fifth term: evaluate the expression for n=5:

$a_5=\frac{8(5)}{5+8}=\frac{40}{13}$Then, the first five terms of the given sequence are:a1=8/9a2=8/5a3=24/11a4=8/3a5=40/13