Question

Two electrons in an atom are separated by 1.5 ✕ 10-10 m, the typical size of an atom. what is the electric force between them?

Answer 1

Answer:The electric force between them is $1.024\times 10^{-17} N$.

Explanation:

Charge on an electron = $q_1=q_2=-1.6\times 10^{-19} C$

Distance between the two electrons = $r=1.5\times 10^{-10} m$

The Electric force between two electrons is given by :

$F_e=k\times \frac{q_1\times q_2}{r^2}$

$F_e=9\times 10^9 N m^2/C^2\times \frac{-1.6\times 10^{-19} C\times -1.6\times 10^{-19} C}{(1.5\times 10^{-10} m)^2}=1.024\times 10^{-17} N$

The electric force between them is $1.024\times 10^{-17} N$.

Answer 2

The electric force between the two electrons is 1.024×10¯⁸ N

Data obtained from the question

• Distance apart (r) = 1.5×10¯¹⁰ m
• Electrical constant (K) = 9×10⁹ Nm²/C²
• Charge of electron = q₁ = q₂ = 1.6×10¯¹⁹ C

• Force (F) =?

How to determine the force of attraction between the two electrons

F = Kq₁q₂ / r²

F = (9×10⁹ × 1.6×10¯¹⁹ × 1.6×10¯¹⁹) / (1.5×10¯¹⁰)²

F = 1.024×10¯⁸ N

Thus, the force between them is 1.024×10¯⁸ N

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