Question

A computer center charges $0.59 to scan each image. How many images must John scan before his total costis less than getting scanned images at the computer center?

Answer 1

Data:

Computer scanner and supplies: $215.70

Scan images: $0.34 each

Total cost: C

Number of images: n

$C=215.70+0.34n$

Computer center charges $0.59 to scan each image:

Charge of scanner in computer center: S

$S=0.59n$

How many images must John scan before his total cost (C) is less than getting scanned images at the computer center (S)?

$\begin{gathered} CSolve the inequality;

Subtract 0.34n in both sides of the inequality:

[tex]\begin{gathered} 215.70+0.34n-0.34n<0.59n-0.34n \\ 215.70<0.25n \end{gathered}$

Divide both sides of the inequality by 0.25:

[tex]\begin{gathered} \frac{215.70}{0.25}<\frac{0.25}{0.25}n \\ \\ 862.8Then, John must scan more than 863 (as you cannot scan a part of a image approximate to the next whole number) before his total cost (C) is less than getting scanned images at the computer center (S