Herricks Elementary school is holding a carnival to raise money for new computers. A committee of 32 students in charge of organizing the carnival and selling ticket. The committee hoped to sell 768 tickets. Part A- How many tickets must each student on the committee sell to reach the goal?Part B If each ticket costs $13, how much money will each student on the committee raise for the new computers?Part C- If the committee raises 8, 905 in total, how many tickets were sold?

Respuesta :

A)24 tickets

B) $312

C) 685 tickets

A) Considering that each student is going to pick the same number of tickets to sell, we can write this out:

[tex]\frac{768}{32}=24[/tex]

So each student on the committee must sell 24 tickets.

B) Consider that the price of that ticket was given, now we can multiply those:

[tex]24\times13=312[/tex]

Each one of those 32 students selling 24 tickets will raise $312 for the new computer.

C) We can find that, by dividing the total income by the price of each ticket:

[tex]\frac{8905}{13}=685[/tex]

So the answer is:

A)24 tickets

B) $312

C) 685 tickets

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