The molar volume of a substance is defined as the volume occupied by one mole. We can find this volume under the STP conditions mentioned (P=1atm and t= 273.15K) using the ideal gas equation that tells us:
[tex]PV=nRT[/tex]Where,
P is the pressure of the gas, 1atm.
V is the volume of the gas, this is the unknown value.
n is the number of moles, in this case, will be 1 mol.
R is a constant, 0.08206 L-atm/mole-K
T is the temperature, 273.15K
Now, we clear the volume, V. And we replace the known data:
[tex]\begin{gathered} V=\frac{nRT}{P} \\ V=\frac{1mol\times0.08206\frac{atm.L}{mol.K}\times273.15K}{1atm} \\ V=\frac{1\times0.08206\times273.15}{1}L \\ V=22.4L \end{gathered}[/tex]The molar volume of any gas at STP is 22.4L. Second option.
