Question

cylindrical barrel has a radius of 2.1 ft and a height of 14 ft. Doubling which dimension(s) will double theolume of the barrel?

Answer 1

ANSWER:

Height

STEP-BY-STEP EXPLANATION:

The volume of a cylinder is given as follows:

$\begin{gathered} V=\pi\cdot r^2\cdot h \\ \text{ therefore:} \\ V=\pi\cdot(2r)^2\cdot h=4\pi\cdot r^2\cdot h=4V \\ V=\pi\cdot r^2^{}\cdot2h=2\pi\cdot r^2\cdot h=2V \end{gathered}$

If we double the radius, the volume would be 4 times greater, while if we double the height, the volume would be double.