Question

If PT=3c and RT=c+14, find the value of c that makes quadrilateral PQRS a parallelogram.SRQPTc=Submit

Answer 1

Explanation

We are given the following:

$\begin{gathered} PT=3c \\ RT=c+14 \end{gathered}$

We are required to determine the value of c for which the quadrilateral PQRS is a parallelogram.

We know that one of the properties of a parallelogram is that the two diagonals bisect each other.

Thus, we have:

$\begin{gathered} PT=RT \\ 3c=c+14 \\ 3c-c=14 \\ 2c=14 \\ \frac{2c}{2}=\frac{14}{2} \\ c=7 \end{gathered}$

Hence, the answer is:

$c=7$