Respuesta :

Given expression is

[tex]\frac{-z^2(1-2x)}{y-x}[/tex]

Given

[tex]x=-2,y=-3,z=5[/tex]

Substituting in the given expression,

[tex]\begin{gathered} \frac{-z^2(1-2x)}{y-x}=\frac{-(5)^2(1-2(-2))}{-3-(-2)} \\ =\frac{-25(1+4)}{-1} \\ =125 \end{gathered}[/tex]

Hence, the value of the given expression is 125.

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