Question

Plot points between and beyond the x-intercepts and the vertical asymptote. Evaluate the function at -7, -6, -1, and 8.112X-72x+x-20f(x)=x-5(Simplify your answers.)-60112180

Answer 1

Replace each x value and solve.

x = -7

$\frac{x^{^2}+x-20}{x-5}=\frac{(-7)^{^2}+(-7)\text{ -20}}{-7-5}=\frac{49-27}{-12}=\frac{22}{-12}=-11/6$

x= -6

$\frac{(-6)^2+(-6)-20}{-6-5}=\frac{36-26}{-11}=-10/11$

x= -1

$\frac{(-1)^{^2}+\text{ \lparen-1\rparen - 20}}{-1-5}=\frac{1-1-20}{-6}=\frac{-20}{-6}=10/3$

x=11/2

$\frac{(11/2)^{^2}+(11/2)-20}{11/2\text{ -5}}=\frac{121/4+11/2-20}{1/2}=\frac{63/4}{1/2}=63/2$

x=8

$\frac{(8)^{^2}+8-20}{8-5}=\frac{64+8-20}{3}=\frac{52}{3}$