Question

Find the tangent of ZS.S2-/11Q3-67-12R.Write your answer in simplified, rationalized form. Do not round.tan (S) =

Answer 1

we are asked to determine the tangent of angle S. To do that let's remember the definition of the tangent function:

$\tan s=\frac{opposite}{adjacent}$

Replacing the values we get:

$\tan s=\frac{3\sqrt[]{6}}{2\sqrt[]{11}}$

rationalizing the expression, by multiplying numerator and denominator by the square root of 11:

$\tan s=\frac{3\sqrt[]{6}\times\sqrt[]{11}}{2\sqrt[]{11}\times\sqrt[]{11}}$

Solving the operations:

$\tan s=\frac{3\sqrt[]{6(11)}}{2(11)}$$\tan s=\frac{3\sqrt[]{66}}{22}$