Question

2. A capacitor has a capacitance of 1.50 x 10-10 F. How much charge is stored when the potential difference is 1.75 V?

Answer 1

The charge in a capacitor is given by:

$Q=CV$

plugging the values given we have that:

$\begin{gathered} Q=(1.5\times10^{-10})(1.75) \\ Q=2.625\times10^{-10} \end{gathered}$

Therefore the charge in the capacitor is:

$2.625\times10^{-10}\text{ C}$