You have the following system of equations:
[tex]\begin{gathered} 5x+4y=9 \\ x+2y=3 \end{gathered}[/tex]In order to solve the previous equation, you first multiply by -2 the second equation:
[tex]\begin{gathered} (x+2y=3)(-2) \\ -2x-4y=-6 \end{gathered}[/tex]Next, you add the first equation of the system with the previous result:
5x + 4y = 9
-2x - 4y = -6
3x + 0 = 3
Next, you solve the previous result for x:
[tex]\begin{gathered} 3x=3 \\ x=\frac{3}{3}=1 \end{gathered}[/tex]Next, you replace the previous value of x into one of the equation of the system. For instance, you use:
[tex]\begin{gathered} x+2y=3 \\ 1+2y=3 \\ 2y=3-1 \\ 2y=2 \\ y=\frac{2}{2}=1 \end{gathered}[/tex]Hence, the solution to the given system of equations is:
x = 1
y = 1