[tex]\begin{gathered} CE=EA=AB \\ \text{let them be represented by x} \end{gathered}[/tex][tex]\begin{gathered} x+x+x+BD=30 \\ 3x+6=30 \\ 3x=30-6 \\ 3x=24 \\ \text{divide both sides by 3} \\ \frac{3x}{3}=\frac{24}{3} \\ x=8 \end{gathered}[/tex]
therefore, CE = 8, EA = 8 and AB = 8
[tex]\begin{gathered} EB=EA+AB \\ EB=8+8=16 \end{gathered}[/tex]
the value of EB = 16
