Question

need some help pleaseSolve the next equation3x^2+x-6=0

Answer 1

We have the next equation

$3x^2+x-6=0$

In order to solve this equation, we will use the next formula

$x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

where

a=3

b=1

c=-6

we substitute the values and reduce

$\begin{gathered} x_{1,2}=\frac{-1\pm\sqrt[]{1^2-4(3)(-6)}}{2(3)} \\ x_{1,2}=\frac{-1\pm\sqrt[]{73}}{6} \\ \end{gathered}$

if we have a second-degree equation we will have two solutions

first solution

$x_1=\frac{-1+\sqrt[]{73}}{6}=1.257$

the second solution is

$x_1=\frac{-1-\sqrt[]{73}}{6}=1.59$

the two solutions of the equation are

$x_1=1.257,_{}x_2=1.59$