Question

2(3-b)+5(b-3)^2 write as a product of two polynomials

Answer 1

From the problem, we have the expression :

$2(3-b)+5(b-3)^2$

We need a common factor to be extracted from the expression, (3 - b) when multiplied to -1 will be (b - 3).

$-2(b-3)+5(b-3)^2$

Now we can factor out (b- 3)

$\begin{gathered} (b-3)\lbrack-2+5(b-3)\rbrack \\ \Rightarrow(b-3)\lbrack-2+5b-15\rbrack \\ \Rightarrow(b-3)(5b-17) \end{gathered}$

The answer is (b - 3)(5b - 17)