Respuesta :

Given;

There are given that the polynomial:

[tex]P(x)=-2x^4-4x^3+4x^2-7[/tex]

Explanation:

To find the quotient and remainder, we need to find the value of P(-2):

Then,

[tex]\begin{gathered} P(x)=-2x^{4}-4x^{3}+4x^{2}-7 \\ P(-2)=-2(-2)^4-4(-2)^3+4(-2)^2-7 \\ P(-2)=-2(16)-4(-8)+4(4)-7 \\ P(-2)=-32+32+16-7 \end{gathered}[/tex]

Then,

[tex]\begin{gathered} P(-2)=-32+32+16-7 \\ P(-2)=16-7 \\ P(-2)=9 \end{gathered}[/tex]

So, the remainder is 9.

Now,

For the quotient:

Divide the given polynomial by (x+2):

So,

[tex]\frac{-2x^4-4x^3+4x^2-7}{x+2}=-2x^3+4x-8[/tex]

Final answer:

Hence, the quotient, remainder, and the value for P(-2) is shown below:

[tex]\begin{gathered} Quotient:--2x^2+4x-8 \\ Remainder:9 \\ P(-2)=9 \end{gathered}[/tex]

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