Question

SandwichSideDrinkJr. Bacon Cheeseburger(65%) Fries (63%)Coke(33%)Crispy Chicken Sandwich(35%) Salad (17%)Diet Coke(18%)Baked Potato (20%) Dr. Pepper (26%)Sprite (23%)So based on these sales numbers, whatare the odds that the next customerorders a Jr. Bacon Cheeseburger, fries orpotato, and a Dr. Pepper?

Answer 1

It is given that the probability of odering a Cheeseburger, fries or potato, and a Dr. Pepper is given by:

$\begin{gathered} P(A)=P(C)\times(P(F)+P(P))\times P(DP) \\ P(A)=0.65\times(0.63+0.2)\times0.26 \\ P(A)=0.14027 \end{gathered}$

Hence the probability is 14%.

Option B is correct.