Using the following property of the fractions:
[tex]\frac{a}{b}+\frac{c}{b}=\frac{a+c}{b}[/tex]Therefore:
[tex]\begin{gathered} \frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}=\frac{1+1+1+1+1+1}{5}=\frac{6}{5} \\ so\colon \\ 6\times\frac{1}{5}\equiv\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5} \end{gathered}[/tex]