Question

2) A gas is held in a sealed glass container. The initial pressure and temperature are 0.150 atm and 72 ° C. If the final temperature is 157 ° C, what is the final pressure (in atmospheres)?

Answer 1

Answer:

The final pressure is 0.3297atm.

Explanation:

1st) The given information from the exercise is:

- Initial pressure (P1): 0.150atm

- Initial temperature (T1): 72°C

- Final temperature (T2): 157°C

2nd) To calculate the final pressure, we can use the Gay-Lussac's formula, by replacing the values:

$\begin{gathered} \frac{P_1}{T_1}=\frac{P_2}{T_2} \\ \frac{0.150atm}{72°C}=\frac{P_2}{157°C} \\ 0.0021\frac{atm}{°C}=\frac{P_2}{157°C} \\ 0.0021\frac{atm}{°C}*157°C=P_2 \\ 0.3297atm=P_2 \end{gathered}$

So, the final pressure is 0.3297atm.