Question

2. How much Heat will be absorbed when 14 grams of Nitrogen reacts with excess 02according to the following equation?N2 + 02 --> 2NOH = 200 kJ

Answer 1

Answer:

99.93kJ

Explanations:

Given the chemical reaction expressed as:

$N_2+O_2\rightarrow2NO\text{ }\triangle H=200kJ$

From the reaction, 1 mole of nitrogen absorbs 200kJ of heat.

Determine the mole of nitrogen

$\begin{gathered} mole\text{ of N}_2=\frac{mass}{molar\text{ mass}} \\ mole\text{ of N}_2=\frac{14g}{28.02g\text{/mol}} \\ mole\text{ of N}_2=0.4996moles \end{gathered}$

The amount of energy 0.4496moles of N2 will absorb is given as:

$\begin{gathered} energy\text{ absorbed by }N_2=0.4496\times200 \\ energy\text{ absorbed by }N_2=99.93kJ \end{gathered}$

Hence the amount of heat that will be absorbed when 14 grams of Nitrogen reacts with excess O2 is 99.93kJ