The slope intercept form of a line is:
[tex]y=mx+b[/tex]Then we can write each of the equations as:
[tex]\begin{gathered} 3x+y=5 \\ y=5-3x \\ y=-3x+5 \end{gathered}[/tex][tex]\begin{gathered} -9x-3y=12 \\ -3y=12+9x \\ y=\frac{12}{-3}+\frac{9x}{-3} \\ y=-4-3x \\ y=-3x-4 \end{gathered}[/tex]We have parallel lines, as they both have the same slope (m=-3).
If we graph the lines, we get:
The lines don't intersect, so we have no solution.
We can demonstrate this as:
[tex]\begin{gathered} 3x+y=5 \\ -9x-3y=12\longrightarrow3x+y=\frac{12}{-3}=-4 \\ \longrightarrow3x+y=5\ne-4\longrightarrow\text{ no solution (they are not equal)} \end{gathered}[/tex]