Question

The diagram shows two parallel lines cut by a traversal If the measure of <2=(3y-8)°, what is the measure of <7?A. (3y-8)°B. (172-3y)°C. (3y-98)°D. (188- 3y)°

Answer 1

When we have two parallel lines cut by a transversal, the corresponding angles <2 and <6 are equal (congruent). Since the angle <7 is a vertical angle with respect to < 6, then <7 and <6 are congruent or have the same measure. Therefore, we have:

$m\measuredangle2\cong m\measuredangle6\cong m\measuredangle7=(3y-8)$

Then, the answer is option A, (3y - 8) degrees (because of the congruency of the angles).