Question

4y + 12 = 0Find two points on the line to be graphed

Answer 1

Given the line:

$4y+12=0$

We simplify to have:

$\begin{gathered} 4y=-12 \\ y=-\frac{12}{4} \\ y=-3 \end{gathered}$

The line y=-3 is a horizontal line passing through y=-3.

Two points on the line that can be graphed are:

$\begin{gathered} (1,-3) \\ (5,-3) \end{gathered}$

You can pick any value of x. The value of y has to remain constant.