Respuesta :

Solution

Note: Equation of a Line os given as

[tex]y=mx+c[/tex]

We are given that the slope is -4/5

That is m = -4/5

[tex]y=-\frac{4}{5}x+c[/tex]

It has x intercept of 3, that is the point (3, 0)

Substituting we have

[tex]\begin{gathered} y=-\frac{4}{5}x+c \\ 0=-\frac{4}{5}(3)+c \\ c=\frac{12}{5} \\ Thus,\text{ we have} \\ y=-\frac{4}{5}x+\frac{12}{5} \end{gathered}[/tex]

The graph of the line is

Ver imagen OluwatamiloreW657439
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