Graph the line with slope of -4/5 and on the x intercept of 3

Solution
Note: Equation of a Line os given as
[tex]y=mx+c[/tex]We are given that the slope is -4/5
That is m = -4/5
[tex]y=-\frac{4}{5}x+c[/tex]It has x intercept of 3, that is the point (3, 0)
Substituting we have
[tex]\begin{gathered} y=-\frac{4}{5}x+c \\ 0=-\frac{4}{5}(3)+c \\ c=\frac{12}{5} \\ Thus,\text{ we have} \\ y=-\frac{4}{5}x+\frac{12}{5} \end{gathered}[/tex]The graph of the line is