Given:
The difference between two numbers is 22.
The sum of twice the smaller number and 3 times the greater number is 246.
Required:
To find the two numbers.
Explanation:
Let the two numbers be x and y.
Let y be the smaller number.
The difference between two numbers is 22.
[tex]x-y=22[/tex]The sum of twice the smaller number and 3 times the greater number is 246.
[tex]2y+3x=246[/tex]Now
[tex]\begin{gathered} 2y+3(22+y)=246 \\ 2y+66+3y=246 \\ 5y=246-66 \\ 5y=180 \\ y=\frac{180}{5} \\ y=36 \end{gathered}[/tex]Now x is,
[tex]\begin{gathered} x-36=22 \\ x=22+36 \\ x=58 \end{gathered}[/tex]Final Answer:
The two numbers are 58 and 36.