Respuesta :

We are asked to determine the half-life of an isotope. To do that we will use the following formula:

[tex]T=\frac{ln(2)}{\lambda}[/tex]

Where:

[tex]\begin{gathered} T=\text{ half-life} \\ \lambda=\text{ decay constant} \end{gathered}[/tex]

Now, we plug in the values:

[tex]T=\frac{ln(2)}{0.00567}[/tex]

Solving the operations:

[tex]T=122.25[/tex]

Therefore, the half-life is 122.25

RELAXING NOICE
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