Question

6x2 = x + 2Write the quadratic equation in standard form:( a )x2 + ( b )x + ( c ) = 0Identify the values of a, b, and c.a =-b =C=Substitute these values into the quadratic formula and simplify:x = -(b)£/( b )2 –4()()2( a )

Answer 1

6x² = x + 2

Subtracting x and 2 at both sides:

6x² - x - 2 = x + 2 - x - 2

6x² - x - 2 = 0

where

a: 6

b: -1

c: -2

Substituting these values into the quadratic formula:

$\begin{gathered} x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x_{1,2}=\frac{1\pm\sqrt[]{(-1)^2-4(6)(-2)}}{2(6)} \\ x_{1,2}=\frac{1\pm\sqrt[]{49}}{12} \\ x_1=\frac{1+7}{12}=\frac{2}{3} \\ x_2=\frac{1-7}{12}=-\frac{1}{2} \end{gathered}$