The given expression is:
[tex]1250^{\frac{3}{4}}[/tex]Find the prime factorization of the number 1250:
[tex]1250=2\times5^4[/tex]Therefore,
[tex]\begin{gathered} 1250^{\frac{3}{4}}=(2\times5^4)^{\frac{3}{4}}=5^{4\times\frac{3}{4}}\times2^{\frac{3}{4}} \\ =5^3\times2^{\frac{3}{4}} \\ =125(\sqrt[4]{2})^3 \end{gathered}[/tex]Therefore, the number that remains under the radical is 2.
Hence, the correct answer is 2