Respuesta :

The given expression is:

[tex]1250^{\frac{3}{4}}[/tex]

Find the prime factorization of the number 1250:

[tex]1250=2\times5^4[/tex]

Therefore,

[tex]\begin{gathered} 1250^{\frac{3}{4}}=(2\times5^4)^{\frac{3}{4}}=5^{4\times\frac{3}{4}}\times2^{\frac{3}{4}} \\ =5^3\times2^{\frac{3}{4}} \\ =125(\sqrt[4]{2})^3 \end{gathered}[/tex]

Therefore, the number that remains under the radical is 2.

Hence, the correct answer is 2

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