Respuesta :

We have the following:

[tex]2x^2+8x=12[/tex]

solving for x:

[tex]\begin{gathered} 2x^2+8x=12 \\ x^2+4x=6 \\ x^2+4x+2^2=6+2^2 \\ (x+2)^2=10 \\ x+2=\sqrt{10}\rightarrow x=\sqrt[]{10}-2 \\ x+2=-\sqrt[]{10}\rightarrow x=-\sqrt[]{10}-2 \end{gathered}[/tex]

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