Question

If you have a sample size of 4 and a population standard deviation of 12, what is your standard error of the mean?ANDIf you have a population standard deviation of 2 ad a sample size of 9, what is your standard error of the mean?

Answer 1

The standard error is given by the formula:

$SE=\frac{\sigma}{\sqrt[]{n}}$

Where: σ is the standard deviation and (n) is the number of samples

Given: a sample size of 4 and a population standard deviation of 12

So, n = 4 and σ = 12

So, the standard error =

$SE=\frac{12}{\sqrt[]{4}}=\frac{12}{2}=6$

And, If you have a population standard deviation of 2 and a sample size of 9

The standard error will be =

$SE=\frac{2}{\sqrt[]{9}}=\frac{2}{3}$