Question

Write an equation in each sentence. Analyze and solve.3. Find three consecutive integers whose sum is 99. Find the integers.

Answer 1

Given that the Sum of three consecutive integers is:

$99$

Let be:

- The first integer:

$n$

- The second integer:

$n+1$

- And the third integer:

$n+2$

By definition, the Sum is the result of an Addition.

Therefore, in this case, you can set up the following equation:

$n+(n+1)+(n+2)=99$

When you solve for "n", you get:

$n+n+1+n+2=99$$3n+3=99$$3n=99-3$$3n=96$$\begin{gathered} n=\frac{96}{3} \\ \\ n=32 \end{gathered}$

Now that you know that first integer, you can determine that the other consecutive integers are:

$n+1=32+1=33$$n+2=32+2=34$

Hence, the answer is:

$\begin{gathered} 32 \\ 33 \\ 34 \end{gathered}$