Multiplying 9/8 and the first equation we get:
[tex]-\frac{63}{8}x-9y=\frac{81}{8}\text{.}[/tex]
Adding the above equation and the second equation of the system we get:
[tex]-\frac{63}{8}x-4x=\frac{81}{8}-22.[/tex]
Adding like terms, we get:
[tex]-\frac{95}{8}x=-\frac{95}{8}\text{.}[/tex]
Therefore:
[tex]x=1.[/tex]
Subtituting x=1 in the first equation, we get:
[tex]-7-8y=9.[/tex]
Solving the above equation for y, we get:
[tex]\begin{gathered} -8y=9+7, \\ -8y=16, \\ y=-2. \end{gathered}[/tex]
Answer:
[tex]x=1,\text{ y=-2.}[/tex]
