We know that the perimeter of a squate is (Where x is the side of the square):
[tex]P=4x[/tex]and we know that the area is:
[tex]A=x^2[/tex]So we can repace the area to find x so:
[tex]\begin{gathered} 25=x^2 \\ x=\sqrt[]{25}=5 \end{gathered}[/tex]So the perimeter will be:
[tex]P=4\cdot5=20[/tex]So the perimeter is 20 feet