Question

An iron rod with an initial length of 12.64 m has its temperature raised from 9o C to 38.10o C. If iron has a coefficient of thermal expansion of 12x10-6 1/oC, what is the change in length of the rod in mm?

Answer 1

We will have the following:

First, we remember that:

$\Delta L=\alpha\ast L_0\ast\Delta T$

So:

$\begin{gathered} \Delta L=(12\ast10^{-6}1/C)(12.64m)(38.1C-9C)\Rightarrow\Delta L=4.413888\ast10^{-3}m \\ \\ \Rightarrow\Delta L\approx4.41mm \end{gathered}$

So, the change in length of the rod is approximately 4.41 mm.