Respuesta :

ANSWER

C. Power rule

E. Equality rule

EXPLANATION

The power rule of logarithms is:

[tex]\log a^b=b\log a[/tex]

It can be applied in both ways. This means that in this expression we can put the power back:

[tex]\begin{gathered} 3\log y=\frac{1}{2}\log x \\ \log y^3=\log x^{1/2} \end{gathered}[/tex]

So first we would use the power rule.

Then, we have log on both sides. The equality rule is:

[tex]\begin{gathered} \text{if }\log a=\log b \\ \text{then }a=b \end{gathered}[/tex]

So for this expression:

[tex]\begin{gathered} \log y^3=\log x^{1/2} \\ y^3=x^{1/2} \end{gathered}[/tex]

So next we would apply the equality rule.

And then we would finish solving the equation:

[tex]y=x^{1/6}[/tex]

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