Which properties would be used to solve the logarithmic expression

ANSWER
C. Power rule
E. Equality rule
EXPLANATION
The power rule of logarithms is:
[tex]\log a^b=b\log a[/tex]It can be applied in both ways. This means that in this expression we can put the power back:
[tex]\begin{gathered} 3\log y=\frac{1}{2}\log x \\ \log y^3=\log x^{1/2} \end{gathered}[/tex]So first we would use the power rule.
Then, we have log on both sides. The equality rule is:
[tex]\begin{gathered} \text{if }\log a=\log b \\ \text{then }a=b \end{gathered}[/tex]So for this expression:
[tex]\begin{gathered} \log y^3=\log x^{1/2} \\ y^3=x^{1/2} \end{gathered}[/tex]So next we would apply the equality rule.
And then we would finish solving the equation:
[tex]y=x^{1/6}[/tex]