We have to evaluate:
[tex]7\frac{1}{4}\cdot2^2+(8\frac{1}{2}-2)\div3[/tex]We then can write:
[tex]\begin{gathered} 7\frac{1}{4}\cdot2^2+(8\frac{1}{2}-2)\div3 \\ 7\frac{1}{4}\cdot4+(6\frac{1}{2})\div3 \\ (7\cdot4+\frac{1}{4}\cdot4)+(\frac{6}{3}+\frac{1}{2\cdot3}) \\ (28+1)+(2+\frac{1}{6}) \\ (28+1+2)+\frac{1}{6} \\ 31+\frac{1}{6} \\ 31\frac{1}{6} \end{gathered}[/tex]Answer: 31 1/6
