In a isosceles triangle. one angle is 9° greater than each of the other two equal angles. find the measure of all three angles
suppose the 'other two angles' measure =x degrees. then the first-mentioned angle has to measure = x+9
Sum of the angle in a triangle = 180°
[tex]\begin{gathered} 9+x+x+x\text{ = 180} \\ 9+3x=180 \\ 3x=180-9 \\ 3x=171 \\ x=\frac{171}{3} \\ x=57^0 \end{gathered}[/tex]
Therefore the measure of all the three angle will be
57 , 57 , 57+9 = 66
Hence the final answer are 57 , 57 and 66
